A technician pushes a 50-lb box 4 feet in 2 seconds. What is the rate of work done?

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Multiple Choice

A technician pushes a 50-lb box 4 feet in 2 seconds. What is the rate of work done?

Explanation:
To determine the rate of work done, we can start by calculating the work performed and then dividing it by the time taken. The work done can be stated as the force applied (weight of the box) multiplied by the distance moved. In this scenario, the box has a weight of 50 pounds and is moved over a distance of 4 feet. To find the work done: Work = Force × Distance Work = 50 lb × 4 ft Work = 200 ft-lb Next, to find the rate of work, we need to divide the total work by the time taken, which is 2 seconds: Rate of Work = Work / Time Rate of Work = 200 ft-lb / 2 s Rate of Work = 100 ft-lb/s This shows that the rate of work done while moving the 50-lb box is 100 ft-lb/s. This calculation aligns with the definition of power in physics, where power is the rate at which work is done over a specific period. Therefore, the rate of work done in this scenario is accurately identified as 100 ft-lb/s.

To determine the rate of work done, we can start by calculating the work performed and then dividing it by the time taken. The work done can be stated as the force applied (weight of the box) multiplied by the distance moved.

In this scenario, the box has a weight of 50 pounds and is moved over a distance of 4 feet. To find the work done:

Work = Force × Distance

Work = 50 lb × 4 ft

Work = 200 ft-lb

Next, to find the rate of work, we need to divide the total work by the time taken, which is 2 seconds:

Rate of Work = Work / Time

Rate of Work = 200 ft-lb / 2 s

Rate of Work = 100 ft-lb/s

This shows that the rate of work done while moving the 50-lb box is 100 ft-lb/s.

This calculation aligns with the definition of power in physics, where power is the rate at which work is done over a specific period. Therefore, the rate of work done in this scenario is accurately identified as 100 ft-lb/s.

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