What will be the volume of a gas after heating 2 ft³ at 50 psia from 300° R to 600° R?

What will be the volume of a gas after heating 2 ft³ at 50 psia from 300° R to 600° R?

• A. 2 ft³
• B. 4 ft³
• C. 6 ft³
• D. 8 ft³

Answer: (B)

To determine the volume of a gas after heating it, we can use the Ideal Gas Law, which states that for a given amount of gas at a constant pressure, the volume of the gas is directly proportional to its absolute temperature. This is described by the formula: \( V_1 / T_1 = V_2 / T_2 \) In this scenario, we have the initial volume (V₁) of 2 ft³ at an initial temperature (T₁) of 300° R, and we need to find the final volume (V₂) at a final temperature (T₂) of 600° R while keeping the pressure constant at 50 psia. Using the Ideal Gas Law, we set up the equation as follows: \( \frac{2 \text{ ft}³}{300 \text{°R}} = \frac{V_2}{600 \text{°R}} \) To find V₂, we can manipulate the equation: \( V_2 = \frac{2 \text{ ft}³ \times 600 \text{°R}}{300 \text{°R}} \) Calculating this gives: \( V_2 = \frac{

To determine the volume of a gas after heating it, we can use the Ideal Gas Law, which states that for a given amount of gas at a constant pressure, the volume of the gas is directly proportional to its absolute temperature. This is described by the formula:

( V_1 / T_1 = V_2 / T_2 )

In this scenario, we have the initial volume (V₁) of 2 ft³ at an initial temperature (T₁) of 300° R, and we need to find the final volume (V₂) at a final temperature (T₂) of 600° R while keeping the pressure constant at 50 psia.

Using the Ideal Gas Law, we set up the equation as follows:

( \frac{2 \text{ ft}³}{300 \text{°R}} = \frac{V_2}{600 \text{°R}} )

To find V₂, we can manipulate the equation:

( V_2 = \frac{2 \text{ ft}³ \times 600 \text{°R}}{300 \text{°R}} )

Calculating this gives:

( V_2 = \frac{